Figure below shows a network of resistance. The effective resistance between points A and B of network is:
Answer & explanation
Correct answer: option 4
Resistance of arm AFE = 3 + 3 = 6 Ω
The arms AFE and AE are in parallel, their effective resistance = $\frac{6 \times 6}{6+6}$ = 3 Ω
Resistance of arm AED = 3 + 3 = 6 Ω
Effective resistance between A and D of portion AFED = $\frac{6 \times 6}{6+6}$ = 3 Ω
Effective resistance between A and C of portion AFEDC = $\frac{(3+3) \times 6}{(3+3)+6}$ = 3 Ω
Resistance of arm AFEDCB = 3 + 3 = 6 Ω
For resistance between A and B, 6 Ω and 3 Ω are in parallel.
Thus effective resistance Rp = $\frac{3 \times 6}{3+6}$ = 2 Ω