Figure below shows a network of resistance. The effective resistance between points A and B of network is:

2 Ω

Resistance of arm AFE = 3 + 3 = 6 Ω

The arms AFE and AE are in parallel, their effective resistance = $\frac{6 \times 6}{6+6}$ = 3 Ω

Resistance of arm AED = 3 + 3 = 6 Ω

Effective resistance between A and D of portion AFED = $\frac{6 \times 6}{6+6}$ = 3 Ω

Effective resistance between A and C of portion AFEDC = $\frac{(3+3) \times 6}{(3+3)+6}$ = 3 Ω

Resistance of arm AFEDCB = 3 + 3 = 6 Ω

For resistance between A and B, 6 Ω and 3 Ω are in parallel.

Thus effective resistance R_p = $\frac{3 \times 6}{3+6}$ = 2 Ω