$16cos^3\frac{\pi}{6}-12cos\frac{\pi}{6}

CUET Preparation Today

Start Free Mocks

Home Questions 8UACMTT7HR

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

$16cos^3\frac{\pi}{6}-12cos\frac{\pi}{6}=$ _____.

Options:

-1

Correct Answer:

Explanation:

16cos³$\frac{π}{6}$ - 12 cos $\frac{π}{6}$

Using formula ,

4cos³A - 3 cosA = cos3A

= 4 ( 4 cos³$\frac{π}{6}$ - 3 cos $\frac{π}{6}$ )

= 4 ( cos 3 × $\frac{π}{6}$ )

= 4 × cos$\frac{π}{2}$

= 0