CUET Preparation Today
$16cos^3\frac{\pi}{6}-12cos\frac{\pi}{6}=$ _____. |
0 2 1 -1 |
0 |
16cos3\(\frac{π}{6}\) - 12 cos \(\frac{π}{6}\) Using formula , 4cos3A - 3 cosA = cos3A = 4 ( 4 cos3\(\frac{π}{6}\) - 3 cos \(\frac{π}{6}\) ) = 4 ( cos 3 × \(\frac{π}{6}\) ) = 4 × cos\(\frac{π}{2}\) = 0 |
