In △ABC, right-angled at B, AB = 7 cm and AC - BC = 1 cm. Find the value of sin C.

$\frac{3}{7}$ $\frac{12}{13}$ $\frac{3}{25}$ $\frac{7}{25}$

$\frac{7}{25}$

by pythagoras theorem 72 + x2 = ( x + 1 )2 49 +x2  = x2 + 1 + 2x  x = 24 So , BC = 24 & AC = 25 Now , sinC = \(\frac{P}{H}\)  = \(\frac{7}{25}\)