CUET Preparation Today
CUET
Physics
Thermodynamics
The internal energy change in a system that has absorbed 12 Kcals of heat and done 23000 J of work is :
48100 J
35900 J
27400 J
24700 J
Q = \(\Delta\) U + W
\(\Delta\) U = Q - W
= 12 x 4.2 x 1000 - 23000
= 27400 J
