Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Thermodynamics

Question:

The internal energy change in a system that has absorbed 12 Kcals of heat and done 23000 J of work is :

Options:

48100 J

35900 J

27400 J

24700 J

Correct Answer:

27400 J

Explanation:

Q = \(\Delta\) U + W

\(\Delta\) U = Q - W

  = 12 x 4.2 x 1000 - 23000

  = 27400 J