The base of a right-angled triangle is 10 and hypotenuse is 20. What is its area?
Answer & explanation
Correct answer: option 1
Applying pythagoras theoram:
(20)2 = (10)2 + (Perpendicular)2
400 = 100 + (Perpendicular)2
300 = (Perpendicular)2
Perpendicular = \(\sqrt { 300}\) = 10\(\sqrt { 3}\)
\(\sqrt { 3}\) = 1.732
Perpendicular = 10 x 1.732 = 17.32
Area = \(\frac{1 }{ 2}\) x b x h
Area = \(\frac{1 }{ 2}\) x 10 x 17.32
Area = 86.6