If x + y + z = 0, then what is the value of $\frac{x}{(yz)^2}+\frac{y}{(xz)^2}+\frac{z}{(xy)^2}$ ?
Answer & explanation
Correct answer: option 2
x + y + z = 0
$\frac{x}{(yz)^2}+\frac{y}{(xz)^2}+\frac{z}{(xy)^2}$
If x + y + z = 0 then
a3 + b3 + c3 = 3abc
$\frac{x}{(yz)^2}+\frac{y}{(xz)^2}+\frac{z}{(xy)^2}$ = \(\frac{x^3 + y^3 + z^3}{(xyz)^2}\)
$\frac{x}{(yz)^2}+\frac{y}{(xz)^2}+\frac{z}{(xy)^2}$ = \(\frac{3xyz}{(xyz)^2}\)
$\frac{x}{(yz)^2}+\frac{y}{(xz)^2}+\frac{z}{(xy)^2}$ = $\frac{3}{xyz}$