Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

The function f defined by $f(x)=(x+2) e^{-x}$ is

Options:

decreasing for all x

decreasing in $(-\infty,-1)$ and increasing in $(-1, \infty)$

increasing for all x

decreasing in $(-1, \infty)$ and increasing in $(-\infty,-1)$

Correct Answer:

decreasing in $(-1, \infty)$ and increasing in $(-\infty,-1)$

Explanation:

We have,

$f(x)=(x+2) e^{-x} \Rightarrow f^{\prime}(x)=e^{-x}-(x+2) e^{-x}=-(x+1) e^{-x}$

∴ $f^{\prime}(x)<0$

$\Rightarrow -(x+1) e^{-x}<0 \Rightarrow-(x+1)<0 \Rightarrow x+1>0 \Rightarrow x>-1$

Hence, f(x) is decreasing in $(-1, \infty)$ and increasing in $(-\infty,-1)$.