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CUET
Physics
Alternating Current
A peak current of 2 A flows through a resistive circuit. What will be the RMS current?
1.41 A
2.83 A
1.43 A
2 A
Irms = \(\frac{Io}{\(\sqrt { 2}\)}\)
Io = 2 A
Irms = 1.414 A
