Five identical capacitors, when connected in series, produce equivalent capacitance of 6 µF. Now these capacitors are rearranged so as to produce the maximum value of equivalent capacitance. This maximum value will be

150 µF

Let C be the capacitance of each capacitor

Then 6 = $\frac{C}{5}$

⇒ C = 30 µF

If these are connected in parallel, then equivalent capacitance will be maximum.

∴ C'  = 30 × 5 = 150 µF