Five identical capacitors, when connected in series, produce equivalent capacitance of 6 µF. Now these capacitors are rearranged so as to produce the maximum value of equivalent capacitance. This maximum value will be
Answer & explanation
Correct answer: option 3
Let C be the capacitance of each capacitor
Then 6 = $\frac{C}{5}$
⇒ C = 30 µF
If these are connected in parallel, then equivalent capacitance will be maximum.
∴ C' = 30 × 5 = 150 µF