If $\begin{Bmatrix}\begin{pmatrix}\frac{sec θ−1}{sec θ+1}\end{pmatrix}\end{Bmatrix}^n = cosec θ − cot θ$ , then n = ? |
1 0.5 -1 -0.5 |
0.5 |
{ ( \(\frac{secθ - 1 }{secθ + 1}\) ) }n = cosecθ - cot θ Let us assume that , θ = 45º { ( \(\frac{sec 45º - 1 }{sec 45º + 1}\) ) }n = cosec 45º - cot 45º { ( \(\frac{√2 - 1 }{√2 + 1}\) ) }n = √2 - 1 Rationalizing on LHS { ( \(\frac{(√2 - 1)² }{2 - 1 }\) ) }n = √2 - 1 So, to satisfy the given equation . n must be = 0.5
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