Match List-I with List-II
Choose the correct answer from the options given below : |
A-I, B-III, C-II, D-IV A-I, B-III, C-IV, D-II A-III, B-I, C-IV, D-II A-III, B-I, C-II, D-IV |
A-III, B-I, C-IV, D-II |
A. $\int \frac{d x}{\sqrt{9 x^2-16}} = \frac{1}{3} \int \frac{d x}{\sqrt{x^2-(\frac{4}{3})^2}}$ $\Rightarrow I =\frac{1}{3} \ln \left|x+\sqrt{x^2-\frac{16}{9}}\right|+C$ $\Rightarrow I=\frac{1}{3} \ln \left|3 x+\sqrt{9 x^2-16}\right|+C$ → III B. $\int \frac{d x}{\sqrt{16-9 x^2}} = \int \frac{d x}{\sqrt{4^2-(3 x)^2}}=\frac{1}{3} \sin ^{-1} \frac{3 x}{4}+C$ → I C. $\int \frac{e^{2 \log x}+1}{e^{2 \log x}-1} d x = \int \frac{x^2+1}{x^2 - 1}dx$ $= \int \frac{x^2-1}{x^2-1} + \frac{2}{x^2-1}dx = \int 1 + \frac{2}{x^2-1} dx = x+\frac{2}{2} \log _e\left|\frac{x-1}{x+1}\right|+C$ → IV D. $\int \frac{1}{1+e^{-x}} d x = \int \frac{e^x}{e^x+1} d x = \log \left|e^x+1\right|+C$ → II |