The correct IUPAC name of the following organic compound is

4-Bromo-3-methylheptanal

The correct answer is Option (3) → 4-Bromo-3-methylheptanal

Step-by-Step IUPAC Naming

To name this organic compound correctly, we follow standard IUPAC nomenclature rules:

Identify the Principal Functional Group:

The molecule contains an aldehyde group ($-CHO$) at the end of the chain. This group takes the highest priority and defines the suffix as "-al".

Determine the Longest Carbon Chain:

Find the longest continuous carbon chain that includes the aldehyde carbon.

• The chain starts at the carbonyl carbon (C1).

• Following the path through the substituents, the chain contains 7 carbons in total.

• A 7-carbon alkane is "heptane," which becomes "heptanal" due to the aldehyde.

Number the Parent Chain:

Start numbering from the aldehyde carbon as C1 to give the principal functional group the lowest possible number:

• C1: Carbonyl carbon ($-CHO$).

• C2: $CH_2$ group.

• C3: Carbon attached to the methyl group ($CH_3$).

• C4: Carbon attached to the bromine atom ($Br$).

• C5, C6, C7: Remaining carbons of the propyl tail.

Identify and Position Substituents:

• There is a methyl group located at position 3.

• There is a bromo group located at position 4.

Assemble the Name Alphabetically:

Substituents are listed in alphabetical order (B for bromo comes before M for methyl):

• 4-bromo + 3-methyl + heptanal = 4-bromo-3-methylheptanal.