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If $x+\frac{1}{x}=8$, then find the value of $\frac{5}{x^2-8 x+2}$. |
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5 |
If $x+\frac{1}{x}=8$ then, x2 + 1 = 8x $\frac{5}{x^2-8 x+2}$ = ? Putting the value of 8x in the given equation = $\frac{5}{x^2-x^2 - 1+2}$ = 5 |
