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In the following nuclear reaction, ${^1_0n} + {^{235}_{92}U} → {^{140}_{54}Xe}+ {^a_bSr}+ 2{^1_0n}$ we have |
$a = 38, b = 94$ $a= 94, b = 38$ $a= 94, b = 40$ $a= 96, b = 38$ |
$a= 94, b = 38$ |
Right Answer not mentioned in NTA Answer key |
