Practicing Success
If a point charge q is placed at the centre of a cube what is the flux linked with the cube? |
$\phi=\frac{1}{\epsilon_0} q$ $\phi=\frac{3}{\epsilon_o} q$ $\phi=\frac{6}{\epsilon_o} q$ $\phi=\frac{1}{6 \in_o} q$ |
$\phi=\frac{1}{\epsilon_0} q$ |
From gauss’s law, flux linked with a closed body is $\left(\frac{1}{\in_0}\right)$ times the charge enclosed. The cube encloses a charge q so flux linked with cube, $\phi=\frac{1}{\epsilon_0} q$ |