A kite is flying at a height of 75 m. If the string makes on angle with the horizontal plane such that $\tan θ = \frac{15}{8}$, then find the length of the string.

85 m

The correct answer is Option (3) → 85 m

Height at which kite is flying, H = 75m

$\tan θ = \frac{15}{8}$ = \(\frac{H}{Base}\)

Base Distance between flyer and the kite, B = \(\frac{75×8}{15}\) = 40

Thus, Length of string, L = sqrt(\( {40}^{2} \) + \( {75}^{2} \)) = 85 m