If $\frac{a}{b}+\frac{b}{a}$ = 0 a ≠ 0, b ≠ 0, then the value of $6(a^3 - b^3)$ is :

0

If $\frac{a}{b}+\frac{b}{a}$ = 0 a ≠ 0, b ≠ 0

then the value of $6(a^3 - b^3)$ = ?

If $\frac{a}{b}+\frac{b}{a}$ = 0

\(\frac{a^2 + b^2}{ab}\) = 0

a² + b² = 0

( a - b )² = a² + b² - 2ab

( a - b )² = 0  - 0 = 0

a - b = 0

we know, a³ - b³ = ( a - b ) ( a² + b² + ab )

6(a³ - b³) =  6( 0) ( a² + b² + ab )

6(a³ - b³)= 0