If $\frac{a}{b}+\frac{b}{a}$ = 0 a ≠ 0, b ≠ 0, then the value of $6(a^3 - b^3)$ is :
Answer & explanation
Correct answer: option 3
If $\frac{a}{b}+\frac{b}{a}$ = 0 a ≠ 0, b ≠ 0
then the value of $6(a^3 - b^3)$ = ?
If $\frac{a}{b}+\frac{b}{a}$ = 0
\(\frac{a^2 + b^2}{ab}\) = 0
a2 + b2 = 0
( a - b )2 = a2 + b2 - 2ab
( a - b )2 = 0 - 0 = 0
a - b = 0
we know, a3 - b3 = ( a - b ) ( a2 + b2 + ab )
6(a3 - b3) = 6( 0) ( a2 + b2 + ab )
6(a3 - b3)= 0