CUET Preparation Today
The torque acting on a magnet of magnetic length 8 cm and pole strength 20 A m placed in a magnetic field of $3 × 10^{-5} T$ at an angle of π/6 rad will be |
$2.4 × 10^{-4} N m$ $2.4 × 10^{-5} N m$ $4.2 × 10^{-3} N m$ $4.2 × 10^{-5} N m$ |
$2.4 × 10^{-5} N m$ |
The correct answer is Option (2) → $2.4 × 10^{-5} N m$ |
