Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Three-dimensional Geometry

Question:

The rate of change (in cm2/s) of the total surface area of a hemisphere with respect to radius r at $r=\sqrt[3]{1.331}$ cm is:

Options:

$66 \pi$

$6.6 \pi$

$3.3 \pi$

$4.4 \pi$

Correct Answer:

$6.6 \pi$

Explanation:

The correct answer is Option (2) → $6.6 \pi$

TSA of hemisphere

$T=3πr^2$

let $\frac{dr}{dt}=1$

$\frac{dT}{dr}=6πr\frac{dr}{dt}$

$=6π×\sqrt[3]{1.331}$

$=6π×1.1$

$=6.6π$ sq. units