The sides of a rhombus are 10 cm in length, and one diagonal is 16 cm. The area of the rhombus is
Answer & explanation
Correct answer: option 4
Applying Pythagoras theorem:
(10)2 = (\(\frac{ 16}{2 }\) )2 + (half of diagonal)2
(10)2= (8)2 + (half of diagonal)2
100 - 64 = (half of diagonal)2
36 = (half of diagonal)2
6 = half of diagonal
Diagonal = 12 cm
Area of the rhombus: \(\frac{1 }{ 2}\) x D1 x D2
Area of rhombus = \(\frac{1 }{ 2}\) x 12 x 16
Area of rhombus = 96 cm2