The sides of a rhombus are 10 cm in length, and one diagonal is 16 cm. The area of the rhombus is

96 sq cm

Applying Pythagoras theorem:

(10)² = (\(\frac{ 16}{2 }\) )² + (half of diagonal)² 

(10)²= (8)² + (half of diagonal)² 

100 - 64 = (half of diagonal)² 

36 = (half of diagonal)² 

6 = half of diagonal

Diagonal = 12 cm

Area of the rhombus: \(\frac{1 }{ 2}\) x D₁ x D₂

Area of rhombus = \(\frac{1 }{ 2}\) x 12 x 16

 Area of rhombus = 96 cm²