Propene on addition with bromine in $CCl_4$ gives
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 1,2-Dibromopropane
Core Concept:
Bromine adds across double bond in nonpolar solvent via electrophilic addition.
Explanation:
When propene reacts with bromine in CCl₄, bromine undergoes electrophilic addition across the double bond. The π-bond breaks and each carbon forms a bond with bromine, resulting in vicinal dibromide formation.
This reaction proceeds via bromonium ion intermediate and results in addition of Br to both carbons of the double bond.
Thus:
Option 1: 1,2-Dibromopropane
Correct because bromine adds across the double bond.
Option 2: 2,2-Dibromopropane
Incorrect because addition is across both carbons, not geminal.
Option 3: Propyl bromide
Incorrect because this would require substitution.
Option 4: 2-Bromopropane
Incorrect because this would require HBr addition.