CUET Preparation Today
If x2 - 101x + 1= 0 and x > 1, then the value of x2 + \(\frac{1}{x^2}\) |
10190 10199 10198 10197 |
10199 |
If x2 - 101x + 1= 0 Divide by x on both sides, x + \(\frac{1}{x}\) =101 ⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2 x2 + \(\frac{1}{x^2}\) = 1012 - 2 = 10199 |
