If x2 - 101x + 1= 0
and x > 1, then the value of
x2 + \(\frac{1}{x^2}\)
Answer & explanation
Correct answer: option 2
If x2 - 101x + 1= 0
Divide by x on both sides,
x + \(\frac{1}{x}\) =101
⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2
x2 + \(\frac{1}{x^2}\) = 1012 - 2 = 10199