Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If x2 - 101x + 1= 0

 and x > 1, then the value of

x2 + \(\frac{1}{x^2}\)

Options:

10190

10199

10198

10197

Correct Answer:

10199

Explanation:

If x2 - 101x + 1= 0

Divide by x on both sides,

x +  \(\frac{1}{x}\) =101

⇒ If x + \(\frac{1}{x}\) = a then x2 + \(\frac{1}{x^2}\) = a2 - 2

x2 + \(\frac{1}{x^2}\)  = 1012 - 2 = 10199