A bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. The average resistance offered by the target is :
Answer & explanation
Correct answer: option 1
using formula, v² = u² + 2as
⇒ 0² = 2² + 2a(0.05)
⇒ a = -4/0.1 = - 40 m/s²
here negative sign of acceleration indicates that it acts just opposite the motion of bullet. hence, it is offered by the target to the bullet.
∴ force offered by the target = mass of bullet × acceleration
= 0.025 kg × 40 m/s²
= 1 N