What will be the momentum of a photon of energy 0.1 MeV in SI unit?

$5.33 × 10^{-23}$

The correct answer is Option (3) → $5.33 × 10^{-23}$

Given:

Energy of photon $E = 0.1\ \text{MeV}$

Conversion to joules:

$1\ \text{eV} = 1.6\times10^{-19}\ \text{J}$

$E = 0.1\times10^{6}\times1.6\times10^{-19} = 1.6\times10^{-14}\ \text{J}$

Formula:

$ p = \frac{E}{c} $

where $c = 3\times10^{8}\ \text{m/s}$

Substitute:

$ p = \frac{1.6\times10^{-14}}{3\times10^{8}} = 5.33\times10^{-23}\ \text{kg·m/s}$

Therefore, the momentum of the photon is $p = 5.33\times10^{-23}\ \text{kg·m/s}$.