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For the following probability distribution :
$E(X^2)$ is equal to : |
3 5 7 10 |
10 |
The correct answer is option (4) → 10 $E(X^2)=∑X^2P(X)$ $=1^2×\frac{1}{10}+2^2×\frac{1}{5}+3^3×\frac{3}{10}+4^2×\frac{2}{5}$ $=\frac{1}{10}+\frac{8}{10}+\frac{27}{10}+\frac{64}{10}=\frac{100}{10}=10$ |
