From a point P, the angle of elevation of a tower is such that its tangent is 3/4 . On walking some distance till point Q towards the tower the tangent of the angle of elevation of the tower becomes 1 . What is the distance travelled (in meters), if the height of the tower is 300 metrer?

100

tan Θ₁ =       3      :     4

                  (AB)    :    (PB)

                    ↓              ↓

                  300         4 × 100 = 400 m

tan Θ₂ =       1      :     1

                  (AB)    :    (QB)

                    ↓              ↓

                  300         300

distance travelled from P to Q = 400 - 300 = 100 m