From a point P, the angle of elevation of a tower is such that its tangent is 3/4 . On walking some distance till point Q towards the tower the tangent of the angle of elevation of the tower becomes 1 . What is the distance travelled (in meters), if the height of the tower is 300 metrer?
Answer & explanation
Correct answer: option 1
tan Θ₁ = 3 : 4
(AB) : (PB)
↓ ↓
300 4 × 100 = 400 m
tan Θ₂ = 1 : 1
(AB) : (QB)
↓ ↓
300 300
distance travelled from P to Q = 400 - 300 = 100 m