If every side of a cube is increased by 16\(\frac{2}{3}\)%, then what will be percentage increase in the surface area -
Answer & explanation
Correct answer: option 3
16\(\frac{2}{3}\)% = \(\frac{1}{6}\)
Surface area (S.A.) = = 6s2
ATQ,
Original : New
side : 6 : 7
S.A. : 6(6)2 : 6 (7)2
: 36 : 49
Here,
S.A. increased by = 49 - 36 = 13
Increased percentage = \(\frac{13}{36}\) × 100 = 36.11%