Match List - I with List - II.

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

Match List - I with List - II.

List - I		List – II
(A)	If A and B are mutually exclusive events, then $P(A \cup B)=$	(I)	$ \frac{P(A \cap B)}{P(B)}, P(B) \neq 0$
(B)	If A and B are independent events, then $P(A \cap B)=$	(II)	$\frac{P(A \cap B)}{P(A)}, P(A) \neq 0$
(C)	If A and B are two events of a sample space of an experiment, then $P(A / B)=$	(III)	$P(A) . P(B)$
(D)	If A and B are two events of a sample space of an experiment, then $P(B / A)=$	(IV)	$P(A)+P(B) $

Choose the correct answer from the options given below :

Options:

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(II), (B)-(III), (C)-(IV), (D)-(I)

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Correct Answer:

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Explanation:

(A) for A, B to be mutually exclusive

$P(A \cup B)=P(A)+P(B)+\underbrace{P(A \cup B)}_{\text { this should be 0 }}$ → (IV)

(B) A, B independent events $\Rightarrow P(A \cap B)$

$=P(A) . P(B)$ → (III)

(D) $P(B / A)=\frac{P(A \cap B)}{P(A)}, P(A) \neq 0$ → (II)