If $f(x) = x^2 - 4x + 13, x ∈R$,then which of the following are correct? (A) $x = 2$ is a stationary point of f(x). Choose the correct answer from the options given below: |
(A), (C) and (D) only (B), (C) and (D) only (A), (B) and (C) only (A), (B) and (D) only |
(A), (B) and (D) only |
The correct answer is Option (4) → (A), (B) and (D) only ** Given: $f(x) = x^{2} - 4x + 13$ Differentiate: $f'(x) = 2x - 4$ Set derivative zero: $2x - 4 = 0$ $x = 2$ So (A) is correct. Second derivative: $f''(x) = 2 > 0$ This means $x=2$ is a point of minima, NOT maxima → (C) is false. Since the parabola opens upward, the function is increasing for $x > 2$ → (B) is correct. Compute $f(2)$: $f(2) = 4 - 8 + 13 = 9$ So (D) is correct. Correct options: (A), (B), (D) |