Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

A point charge q moves from point P to point S along the path PQRS in a uniform electric field E pointing parallel to the positive direction of the x-axis. The coordinate of the points P,Q, R and S are (a, b, 0), (2a, 0, 0), (a, -b, 0) and (0, 0, 0) respectively. The work done by the field in the above process is given by the expression

Options:

qaE

-qaE

q$(\sqrt{a^2+b^2})E$

$3qE\sqrt{a^2+b^2}$

Correct Answer:

-qaE

Explanation:

The work done is independent of the path followed and is equal to $(q \vec{E}) . \vec{r}$, where $\vec{r}$ = displacement vector $\overline{PS}=-a \hat{i}-b \hat{j}$, while $\overline{E}=E \hat{i}$

∴ Work = $q \overline{E} . \overline{r}=-qaE$

∴ (B)