Major product Y in the following reaction is |
The correct answer is Option (4) →
A carboxylic acid reacts with alcohol in presence of acid catalyst to form an ester. This is known as Fischer esterification. Reaction: $\text{Benzoic acid} + \text{Ethanol} \rightarrow \text{Ethyl benzoate} + \text{Water}$ Acid catalyst: conc. $\text{H}_2\text{SO}_4$ or $\text{HCl}$ So product formed is: $\text{C}_6\text{H}_5\text{COOC}_2\text{H}_5$ (Ethyl benzoate) Option 1: $\text{C}_6\text{H}_5\text{COC}_2\text{H}_5$ This is a ketone. Not formed from acid + alcohol reaction. Option 2: $\text{C}_6\text{H}_5\text{CH}_2\text{OH}$ This is benzyl alcohol. Reduction product, not esterification product. Option 3: $C_6H_5COCH_3$ This is acetophenone. Formed via Friedel-Crafts acylation, not esterification. Option 4: $C_6H_5COOC_2H_5$ This is ethyl benzoate. Formed via esterification. Correct. |