Major product Y in the following reaction is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) →
A carboxylic acid reacts with alcohol in presence of acid catalyst to form an ester.
This is known as Fischer esterification.
Reaction:
$\text{Benzoic acid} + \text{Ethanol} \rightarrow \text{Ethyl benzoate} + \text{Water}$
Acid catalyst: conc. $\text{H}_2\text{SO}_4$ or $\text{HCl}$
So product formed is:
$\text{C}_6\text{H}_5\text{COOC}_2\text{H}_5$ (Ethyl benzoate)
Option 1: $\text{C}_6\text{H}_5\text{COC}_2\text{H}_5$
This is a ketone.
Not formed from acid + alcohol reaction.
Option 2: $\text{C}_6\text{H}_5\text{CH}_2\text{OH}$
This is benzyl alcohol.
Reduction product, not esterification product.
Option 3: $C_6H_5COCH_3$
This is acetophenone.
Formed via Friedel-Crafts acylation, not esterification.
Option 4: $C_6H_5COOC_2H_5$
This is ethyl benzoate. Formed via esterification.
Correct.