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CUET
General Test
Numerical Ability
Pipes and Cisterns
Pipes A and B can fill a tank in 12 hours and 16 hours respectively and pipe C can empty the full tank in 24 hours. All three pipes are opened together, but after 4 hours pipe B is closed. In how many hours, the empty tank will be completely filled? |
18 32 28 14 |
18 |
A+ = 12 hrs, B+ = 16 hrs, C- = 24 hrs, ⇒ A + B + C opened for 4 hrs and the B was closed = (4 + 3 - 2) x 4 = 5 x 4 = 20 units, ⇒ Remaining = 48 - 20 = 28 units, ⇒ Time required for A + C to fill remaining cistern = 284−2 = 282 = 14 hrs, ⇒ Total time taken to fill the cistern = 4 + 14 = 18 hrs. |