Consider the following frequency distribution.

Find the median of the distribution?

39

The correct answer is Option (2) → 39

Given Frequency Distribution:

Total frequency (N) = 50

Median Class: The class whose cumulative frequency is just greater than or equal to 25 (N/2)

→ Median class = 30 – 40

Values:

• $l = 30$
• $f = 10$ (frequency of median class)
• $F = 16$ (cumulative frequency before median class)
• $h = 10$ (class width)

Median formula:

$\text{Median} = l + \frac{\frac{N}{2} - F}{f} \cdot h$

Substituting:

$\text{Median} = 30 + \frac{25 - 16}{10} \cdot 10 = 30 + \frac{9}{10} \cdot 10 = 30 + 9 = 39$