Practicing Success

Target Exam

CUET

Subject

Biology

Chapter

Evolution

Question:

In Hardy Weinberg equation, the frequency of heterogygous individuals is represented by :

Options:

q2

p2

2pq

pq

Correct Answer:

2pq

Explanation:
According to the Hardy Weinberg law, the allele and genotype frequencies in a population remain constant in the absence of factors responsible for evolution. 
 It states that the sum of all genotype frequencies can be represented as the binomial expansion of the square of the sum of p and q.
 This sum is equal to one : (p+q)2 = p2 + 2pq + q2 = 1
 "p" is the frequency of the dominant allele,
 "q" is the frequency of the recessive allele. 
 "2pq" is the frequency of heterozygotes in the population.