If sinθ - cosec θ = 11 , find the value of sin2θ + cosec2θ .
Answer & explanation
Correct answer: option 2
Formula I → [ sinθ = \(\frac{1}{cosecθ}\)]
Formula II → [If x - \(\frac{1}{x}\) = n and x2 + \(\frac{1}{x^2}\) = n2 + 2]
sinθ - \(\frac{1}{sinθ}\) = 11
⇒ sin2θ + \(\frac{1}{sin^2θ}\) = (11)2 + 2
⇒ sin2θ + cosec2θ = 121 + 2 = 123