If sinθ - cosec θ = 11 , find the value of sin2θ + cosec2θ .

144 123 119 121

123

Formula I → [ sinθ = \(\frac{1}{cosecθ}\)] Formula II → [If x - \(\frac{1}{x}\) = n and x2 + \(\frac{1}{x^2}\) = n2 + 2] sinθ - \(\frac{1}{sinθ}\) = 11 ⇒ sin2θ + \(\frac{1}{sin^2θ}\) = (11)2 + 2 ⇒ sin2θ + cosec2θ = 121 + 2 = 123