Practicing Success
Time period of oscillation of a bar magnet in a uniform magnetic field is $T_{o}$. The magnet is cut into 3 equal parts transverse to its length. The new time period of oscillation of one part will be: |
$T_o$ $\frac{T_o}{2}$ $\frac{T_o}{3}$ $\frac{T_{o}}{4}$ |
$\frac{T_o}{3}$ |
The correct answer is Option (3) → $\frac{T_o}{3}$ |