Jitin's age 3 years from now will be double the average of Jitin's current age and his age 8 years ago. What was Jitin's age 5 years ago ?
Answer & explanation
Correct answer: option 4
ATQ,
Lets assume Jitin's present age = x
Average of Jitin's present age and 8 years ago = \(\frac{x + x - 8}{2}\)
Given, after 3 years ⇒ x + 3 = 2 x \(\frac{x + x - 8}{2}\)
⇒ x + 3 = 2x - 8
⇒ x = 11
Jitin's age 5 years ago = 11 - 5 = 6 years