If incident ray MP and reflected ray QN are parallel to each other, find the angle θ between the mirrors. |
60° 45° 90° 180° |
90° |
The deviation produced by first mirror $=180-2 i_1$ and the deviation produced by second mirror $=180-2 i_2$. The total deviation is 180° as MP and QN are anti parallel So, $180^{\circ}=360^{\circ}-2\left(i_1+i_2\right)$ ∴ $i_1+i_2=\theta=90^{\circ}$ |