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The value of k, for which is A = \(\begin{bmatrix}k+3 & 2 \\1 & k+4 \end{bmatrix}\) singular matrix is |
-2 -5 Both (a) and (b) None |
Both (a) and (b) |
Finding the determinant and equating it to 0. \((k+3)(k+4) - 2 = 0\) \({ k }^{ 2 } +7k +12 - 2 = 0\) \({ k }^{ 2 }+7k +10= 0\) \((k+2)(k+5)= 0 \) k+2 = 0 or k+5 = 0 So. k=-2 or -5 |
