The value of k, for which is A = \(\begin{bmatrix}k+3 & 2 \\1 & k+4 \end{bmatrix}\) singular matrix is
Answer & explanation
Correct answer: option 3
Finding the determinant and equating it to 0.
\((k+3)(k+4) - 2 = 0\) \({ k }^{ 2 } +7k +12 - 2 = 0\)
\({ k }^{ 2 }+7k +10= 0\) \((k+2)(k+5)= 0 \)
k+2 = 0 or k+5 = 0
So. k=-2 or -5