Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

A charge Q is distributed over two concentric hollow spheres of radii r and R (< r) such that the surface densities are equal. The potential at the common centre is

Options:

$\frac{Q(R^2+r^2)}{4\pi \epsilon_0(r+R)^3}$

$\frac{Q}{r+R}$

zero

$\frac{Q(R+r)}{4\pi \epsilon_0(r^2+R^2)}$

Correct Answer:

$\frac{Q(R+r)}{4\pi \epsilon_0(r^2+R^2)}$

Explanation:

$\text{Let charge on the two spheres are }Q_1 \text{ and }Q_2 \text{ respectively.}$

$ Q_1 + Q_2 = Q$

$ \frac{Q_1}{4\pi r^2} = \frac{Q_2}{4\pi R^2}$

$ Q_2 = \frac{Q_1 R^2}{r^2}$

$Q_1(1+ \frac{R^2}{r^2}) = Q , Q_1  = \frac{Qr^2}{r^2+R^2} , Q_2 = \frac{QR^2}{r^2+R^2}$

$ V = \frac{1}{4\pi \epsilon_0}(\frac{Q_1}{r}+\frac{Q_2}{R}) = \frac{Q(R+r)}{4\pi \epsilon_0(r^2+R^2)}$