The osmotic pressure of a solution at $0^{\circ}\text{C}$ is 2 atm. What will be its osmotic pressure at 819 K?

6 atm

The correct answer is Option (1) → 6 atm

osmotic pressure is proportional to the molarity, C of the solution at a given temperature T. Thus: $\Pi=CRT $

$ \frac{\Pi_1}{\text{T}_1}=\frac{\Pi_2}{\text{T}_2}\Rightarrow\Pi_2=\Pi_1\times\frac{\text{T}_2}{\text{T}_1} $

$ \Pi_2=2\times\frac{819}{273} $

$ \frac{819}{273}=3 $

$ \Pi_2=2\times3=6\ \text{atm} $