Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Match List – I with List – II.

LIST I

 LIST II 

 A. The fourth proportional to 4, 9, 12

 I. 0.12

 B. The mean proportional between 0.08 and 0.18 

 II. $2 \sqrt{3}$ 

 C. The third proportional to 16 and 36 

 III. 27

 D. The mean proportional between $6+3 \sqrt{3}$ and $8-4 \sqrt{3}$ 

 IV. 81

Choose the correct answer from the options given below:

Options:

A-I, B-II, C-III, D-IV

A-III, B-I, C-II, D-IV

A-III, B-I, C-IV, D-II

A-III, B-IV, C-II, D-I

Correct Answer:

A-III, B-I, C-IV, D-II

Explanation:

A. The fourth proportional to 4, 9, 12

 = \(\frac{12 × 9 }{ 4 }\)

= 27 (III)

B. The mean proportional between 0.08 and 0.18 = \(\sqrt {0.8 × 0.18}\)

= 0.12 ( I )

C. The third proportional to 16 and 36 = \(\frac{36 × 36}{ 16 }\) 
= 81

D. The mean proportional between $6+3 \sqrt{3}$ and $8-4 \sqrt{3}$

= \(\sqrt {( 6 + 3√3) × ( 8 - 4√3) }\)

= \(\sqrt { 48 - 24√3 + 24√3 - 36  }\)

 = \(\sqrt { 12  }\)

 = 2\(\sqrt { 3 }\)

 The correct answer is Option (3) → A-III, B-I, C-IV, D-II