In the last term of an Geometric Progression is 1, and the common ration (r) is $\frac{1}{2}$ then, total number of terms in this Geometric progression are _____ if the first term is 16.
Answer & explanation
Correct answer: option 4
Given,
the last term of an Geometric Progression is 1, and the common ration (r) is $\frac{1}{2}$
First term = 16
So, according to the concept, Geometric progression is a series of numbers in which each is multiplied or divided by a fixed number to produce the next.
So, 16 × ($\frac{1}{2}$)n = 1
($\frac{1}{2}$)n= $\frac{1}{16}$
n = 4
and the fifth term is 1.
So there are total 5 terms.