In the last term of an Geometric Progression is 1, and the common ration (r) is $\frac{1}{2}$ then, total number of terms in this Geometric progression are _____ if the first term is 16.

5

Given,

the last term of an Geometric Progression is 1, and the common ration (r) is $\frac{1}{2}$

First term = 16

So, according to the concept, Geometric progression is a series of numbers in which each is multiplied or divided by a fixed number to produce the next.

So, 16 × ($\frac{1}{2}$)ⁿ = 1

($\frac{1}{2}$)ⁿ= $\frac{1}{16}$

n = 4

and the fifth term is 1.

So there are total 5 terms.