The correct answer is Option (1) → $[Fe(NH_3)_4Cl_2]^+$
In coordination chemistry, complexes are classified into two types based on the nature of their ligands:
- Homoleptic complexes: The metal is bound to only one type of donor group (ligand).
- Heteroleptic complexes: The metal is bound to more than one type of donor group (ligand).
Analysis of the Options:
- $[Fe(NH_3)_4Cl_2]^+$: This complex contains two different types of ligands: four ammine ($NH_3$) groups and two chloride ($Cl^-$) ions. Because there is more than one type of ligand, it is heteroleptic.
- showing two types of ligands]
- $[Cr(NH_3)_6]^{3+}$: This complex contains only one type of ligand (six $NH_3$ groups). It is homoleptic.
- $[Co(NH_3)_6]^{3+}$: This complex contains only one type of ligand (six $NH_3$ groups). It is homoleptic.
- $[Mn(CN)_6]^{4-}$: This complex contains only one type of ligand (six $CN^-$ groups). It is homoleptic.
|
