CUET Preparation Today
Two cells of emf E and 2E with internal resistances r and 3r, respectively are connected in parallel. The emf and internal resistance of the combination is: |
$\frac{4}{3}E,\frac{2}{3}r$ $\frac{1}{4}E,\frac{3}{2}r$ $\frac{5}{4}E,\frac{3}{4}r$ $\frac{2}{3}E,\frac{1}{2}r$ |
$\frac{5}{4}E,\frac{3}{4}r$ |
The correct answer is Option (3) → $\frac{5}{4}E,\frac{3}{4}r$ |
