A current of 10 A is flowing in a wire of length 1.2 m. A force of 12 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \( 30^\circ \)
The force on a current-carrying wire in a uniform magnetic field is \( F = I\,l\,B\sin\theta \), where \( \theta \) is the angle between the current and the field.
\( \displaystyle \sin\theta = \frac{F}{I\,l\,B} =\frac{12}{10 \times 1.2 \times 2} = \frac{12}{24} = 0.5 \)
\( \displaystyle \theta = 30^\circ \)