Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Magnetism and Matter

Question:

What is the expression for the equatorial field of a bar magnet at a very large distance?

Options:

\(\frac{μ_{o}}{4π} \frac{2M}{r^{3}}\)

\(\frac{μ_{o}}{4π} \frac{M}{r^{3}}\)

-\(\frac{μ_{o}}{4π} \frac{2M}{r^{3}}\)

-\(\frac{μ_{o}}{4π} \frac{M}{r^{3}}\)

Correct Answer:

-\(\frac{μ_{o}}{4π} \frac{M}{r^{3}}\)

Explanation:

The expression for the equatorial field of a bar magnet at a very large distance : B = -\(\frac{μ_{o}}{4π} \frac{M}{r^{3}}\)