Practicing Success
If $A=[(x,y):x^2+y^2=25]$ and $B=[(x,y):x^2+9y^2=144]$, then A ∩ B contains. |
2 points 3 points 4 points 5 points |
4 points |
$x^2+y^2=25$ $⇒x^2+y^2=5^2$ $x^2+9y^2=144$ $⇒\frac{x^2}{12^2}+\frac{y^2}{4^2}=1$
P, Q, R, S are four points of intersection. Clearly, A ∩ B consists of four points. |