What is the value of (4x^2+9y^2+12xy)/144 ?

$\frac{4x^2+9y^2+12xy}{144}$

( a + b ) = \(\frac{a^3 + b^3}{a^2 + b^2 - ab }\)

= $\frac{(2x+3y)^2}{(12)^2}$

= [\(\frac{2x}{12}\) +  \(\frac{3x}{12}\) ]²

= $(\frac{x}{6}+\frac{y}{4})^2$