If $ x + \frac{1}{15x} = 3, $ then the value of $9x^3 +\frac{1}{375x^3}$ will be :
Answer & explanation
Correct answer: option 1
If $ x + \frac{1}{15x} = 3, $
then the value of $9x^3 +\frac{1}{375x^3}$ = ?
We know that,
If x + y = n
then, $x^3 + y^3$ = n3 - 3 × n × xy
= then, $ x^3+\frac{1}{3375x}$ =33 - 3 × 3 ÷ 15 = \(\frac{132}{5}\)
Multiply the above equation by 9 to get the desired equation,
$9x^3 +\frac{1}{375x^3}$ = \(\frac{132}{5}\) × 9 = \(\frac{1188}{5}\) = 237.6